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In Text Questions Page Number 18 Chapter 2 Science Class 9 NCERT Solutions in Text Question Chapter 2 is Matter Around

In text questions page number 18 Chapter 2: is Matter Around Us Pure Science Class 9 solutions are avalable at ourwebsite to help the students. In text questions page number 18 is solved by our expert teachers. You can get ncert solutions and notes for class 9 chapter 2 absolutely free. NCERT Solutions for class 9 Science Chapter 2: is Matter Around Us Pure will definitely help in improving your marks in CBSE Board examinations.

In text questions page number 18

1. Differentiate between homogeneous and heterogeneous mixtures with examples.
Answer:
Homogeneous Mixtures Heterogeneous Mixtures
1. Homogeneous mixtures have uniform composition. 1. Heterogeneous mixtures have non uniform composition
2. It has no visible boundaries of separation between its constituents. 2. It has visible boundaries of separation between its constituents.
3. Some examples of homogeneous mixtures are: salt in water, sugar in water. 3. Some examples of heterogeneous mixtures are: water and sand, oil and water.

2. How are sol, solution and suspension different from each other?
Answer:

Sol(Colloidal solution) Solution Suspension
1.They are heterogeneous in nature 1.They are homogeneous in nature 1.They are heterogeneous in nature
2. They scatter a beam of light and hence show Tyndall effect. 2. They do not scatter a beam of light and hence do not show Tyndall effect. 2. They do not scatter a beam of light and hence do not show Tyndall effect.
3. They are quite stable 3. They are very stable 3. They are unstable
4. Examples of sol are: milk, blood smoke etc. 4. Examples of solution are: salt in water, sugar in water. 4. Examples of suspension are: sand in water, dusty air

3. To make a saturated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 K. Find its concentration at this temperature.
Answer:
Mass of solute (sodium chloride) =36g
Mass of solvent (water) =100g
Mass of solution = Mass of Solute + Mass of solvent
                          = 36g +100g = 136g

 

 

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